SÃO PAULO, Brazil - Four races into the 2012 IZOD IndyCar Series and Will Power is on a roll. On Sunday in Brazil, he became the first driver to win three straight IndyCar events since 2007.
The Penske driver made it three wins in a row this season, winning the Itaipava São Paulo Indy 300 on April 29. The victory was also Power’s third straight on the Brazil circuit. And, yet, he doesn’t believe he is driving in a dominant fashion.
“You need a bit of luck, good strategy, no mistakes, and that's how you win races,” Power said about his victory. “I wouldn't call it dominating at all. I was driving and giving it everything, absolutely everything I had to keep Ryan (Hunter-Reay) behind. I knew I had to pull some sort of gap, because if you keep him at tow, he would most definitely be able to pass me.”
Not only is Power the first driver, since Scott Dixon in 2007, to win three consecutive races, the victory in São Paulo keeps Penske Racing perfect after four races this year. Helio Castroneves won the IZOD IndyCar Series opener in Florida. It is the first time that owner Roger Penske has opened a season with four wins in his 44 years in auto racing.
Power is the only driver to win the São Paulo race. IndyCar first staged the event in the Brazilian city in 2010.
Takuma Sato finished the São Paulo Indy 300 in third place, behind Power and Hunter-Reay, for his first ever podium finish in the IZOD IndyCar Series. As for the four Brazilian drivers racing in the series, they were all placed in the top 10 at one point in the race. In the end, only hometown-boy Rubens Barrichello remained there.
The win keeps Power atop the IZOD IndyCar Series drivers’ standings, with teammate Castroneves in second and Simon Pagenaud in third. Scott Dixon and James Hinchcliffe
Power is now looking to ride the momentum as the IndyCar schedule takes teams to the Indianapolis Motor Speedway and the 96th running of the Indianapolis 500, on May 27. Power’s best result at the Indy 500 is a fifth-place finish in 2009, his first year with Penske Racing.